Order the following three solutions from smallest to largest pH: (i) 0.030 M Ba(OH)2 (ii) 0.040 M KOH (iii) pure water. (a) i < ii < iii (b) ii < i < iii (c) iii < i < ii (d) ii < iii < i (e) iii < ii < i
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(i) 0.030 M Ba(OH)2: Since Ba(OH)2 dissociates into one Ba²⁺ ion and two OH⁻ ions, the concentration of OH⁻ ions is 2 * 0.030 M = 0.060 M. (ii) 0.040 M KOH: KOH dissociates into one K⁺ ion and one OH⁻ ion, so the concentration of OH⁻ ions is 0.040 M. (iii) Pure Show more…
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