Question

Oxygen gas (O2) can be obtained from the decomposition reaction of potassium chlorate (KClO3): 2KClO3(s) → 2KCl(s) + 3O2(g) a) How many moles of O2 can be produced by the decomposition of 32.8 g KClO3? b) How many grams of KClO3 are required to decompose to produce 50.0 g O2?

Name: oxygen gas o2 can be obtained from the decomposition reaction of potassium chlorate kclo3 2kclo3s 2kcls 3o2g a how many moles of o2 can be produced by the decomposition of 328 g kclo3 b how 65506
Uploaded: 2023-04-21T11:07:32-08:00
Duration: 3 min 21 s
Channel: Madhur L
Description: oxygen gas o2 can be obtained from the decomposition reaction of potassium chlorate kclo3 2kclo3s 2kcls 3o2g a how many moles of o2 can be produced by the decomposition of 328 g kclo3 b how 65506

          Oxygen gas (O2) can be obtained from the decomposition reaction of potassium chlorate (KClO3):
2KClO3(s) → 2KCl(s) + 3O2(g)
a) How many moles of O2 can be produced by the decomposition of 32.8 g KClO3?
b) How many grams of KClO3 are required to decompose to produce 50.0 g O2?

Added by Richard P.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

04/21/2023

Step 1

8 g of KClO3. Given: - Mass of KClO3 = 32.8 g - Molar mass of KClO3 = 122.6 g/mol - Balanced chemical equation: 2KClO3(s) → 2KCl(s) + 3O2(g) Calculate moles of KClO3: Moles of KClO3 = 32.8 g / 122.6 g/mol = 0.2676 mol Use the mole ratio from the balanced chemical Show more…

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Oxygen gas (O2) can be obtained from the decomposition reaction of potassium chlorate (KClO3): 2KClO3(s) → 2KCl(s) + 3O2(g) a) How many moles of O2 can be produced by the decomposition of 32.8 g KClO3? b) How many grams of KClO3 are required to decompose to produce 50.0 g O2?