2KClO3(s) → 2KCl(s) + 3O2(g) Calculate how many grams of oxygen form when each quantity of reactant completely reacts. a. 2.95 g KClO3 b. 0.368 g KClO3 c. 86.1 kg KClO3 d. 25.9 mg KClO3
Added by Francisco U.
Step 1
KClO3: 39.10 (K) + 35.45 (Cl) + 3 * 16.00 (O) = 122.55 g/mol O2: 2 * 16.00 (O) = 32.00 g/mol Now, we can use the stoichiometry of the balanced equation to find the mass of oxygen produced for each given mass of KClO3. a. 2.95 g KClO3 First, convert the mass of Show more…
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