00:02
All right, so we have women's heights are normally distributed with the mean of 6 .63 .5 inches and standardization of 2 .5 inches.
00:12
And the branch of the military requires women's heights to be between 58 and 80 inches.
00:18
Find the percentage of women meet the requirements.
00:23
So here's a nice visual.
00:26
So if here's the mean of 63 right in the middle, then we'd have 58 down here somewhere.
00:32
And the 80 up here, we want to know all.
00:35
This stuff.
00:40
So the way we do that is you're going to find and here's a down here, just be clear, here's 58, and up here it's 80.
00:59
So we knew it's find the area under 80 and subtract the area 58.
01:04
So here we go.
01:05
So a norm.
01:07
Oh, we need to do a z score.
01:09
Well, actually, i don't need to.
01:10
I've got a norm function that does this for me.
01:14
Put in the value i want, which is 80, mean of 60.
01:21
Three and a half.
01:24
The deviation of two and a half.
01:26
And do we want cumulative? yes, we do.
01:33
Let's get some more decimal places.
01:41
So this is like, this is for 80 inches, that's pretty much all, right? because if you add up 63 and a half inches with a standard deviation of two, that's gonna be quite high.
01:56
So for all intents of purposes, that's high.
01:59
And just to make sure this is working right.
02:01
If you do 63 .5, we get half.
02:03
So, it's kind of funny.
02:08
So my function gives us one.
02:10
It's pretty much basically all.
02:13
But then we're going to subtract off the 58, the percentage less than 58...