00:01
Still given that p and q are 100 km apart now a starts from p travel towards q at 10 km per hour and b starts running from q at exactly the same time the same direction as a at 20 km per hour and after one hour that means after one hour that is this part is 20 km he turns back towards a and change his speed at 10 km per hour.
00:50
And after an hour, so that means this part is 10 km, he changed back again at 20 km per hour and he keeps doing this after an hour each time he will change direction and change the speed as well.
01:09
So i want to find how much time will a &b meet for the first time.
01:13
Now the formula for distance speed time is dxt, d for distance, s for speed, t for time.
01:23
Now for them to meet, that is the time t must be the same.
01:28
Now t is distance over speed.
01:31
So for a, the time t is the distance.
01:38
Now i'm going to let x be the distance where both of them will meet.
01:49
So they will meet here.
01:54
So the distance travelled by a will be 100.
01:57
Plus x over its speed of 10 kilometers per hour...