I. Evaluating learning (WRITTEN WORK) Solve the following...

I. Evaluating learning (WRITTEN WORK) Solve the following problems, make predictions based on the results of each experiments. 1. A coin is tossed 80 times. The coin landed on heads 46 times and on tails 34 times. a. Find the probability of landing on tails b. Find the probability of landing on heads 2. A drawer contains 4 black socks, 6 white socks, and 2 brown socks. 2 socks are drawn at randon, one after the other, without replacement. Complete to find each probability. a. P (black, then black) First draw: P (black)= Second draw: P(black)= P(black, then black)= b. P(white,then brown) First draw: P(white)= Second draw: P(brown)= P(white then brown)=

Transcript

00:01 Alright, so the question here is that a coin is just four times, right? so we have been asked to construct the sample space for this experiment.

00:09 And on the basis of that, we have to compute the given probabilities.

00:13 So first of all, the sample space here, this will be that there are four heads, then head, head, head, head, head, and tail, and head.

00:27 Then head, tail, head, head, head, then tail, head, head, head, then head, head, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail, tail.

00:57 And all four are tail so the number of outcomes or the total outcomes here are 16 right now the first part of this question is that what is the probability that there are exactly two heads so the number of favorable outcomes here if we look back so here our number of favorite with two heads is one two three four five six right so our number of favorable outcomes are six right so the probability that there are two heads will be six upon sixteen or this will be equal to three by 13 sorry this is sorry three by eight all right in the next part we have been asked to determine the probability that there are the at least three heads so there are three or more heads so the elements the number of favorable outcomes here will be five.

02:01 That is all four are head or head, head, head, head and tail, head, tail and head, and head, head, head, head, head, head, head, head, right? so here are the probability that there are at least three heads...

Question

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