00:02
Okay, so we have a lab experiment here.
00:04
So i'm just suggesting the numerical values that will come out of the experiment.
00:09
And the experiment is to be verified by the student himself.
00:13
So we have a circuit here that have two resistances arranged in parallel.
00:24
And the supply is 9 volt and the resistances is 100 oom and 50 oom.
00:32
So two resistances are here.
00:35
We have to find the first part is the current across each register and the battery.
00:42
Then the second part is the current across each register, voltage difference across each register suggesting that the register is in series or parallel and the equivalent resistance of the circuit.
00:55
So we'll start with the last part itself.
00:58
So this register is in this type of connection is a certain.
01:03
To be parallel and for the parallel the net equivalent resistance comes out to be r equals to r1 r2 upon r1 plus r2 so we'll use this formula to direct calculate the resistances so it will be 100 cross 50 divided by 150 100 plus 50 so that will be 100 upon 3 om this is the net resistance...