Question

Part A A proton orbits a long charged wire, making $1.40 \times 10^6$ revolutions per second. The radius of the orbit is $2.00$ cm. What is the wire's linear charge density? Express your answer in nanocoulombs per meter. View Available Hint(s) $\lambda = -23.42$ nC/m Submit Previous Answers Incorrect; Try Again; 5 attempts remaining Provide Feedback

Name: part a a proton orbits a long charged wire making 140 times 106 revolutions per second the radius of the orbit is 200 cm what is the wires linear charge density express your answer in nanoco 53154
Uploaded: 2020-08-29T19:08:27-08:00
Duration: 2 min 15 s
Channel: Mayukh Banik
Description: part a a proton orbits a long charged wire making 140 times 106 revolutions per second the radius of the orbit is 200 cm what is the wires linear charge density express your answer in nanoco 53154

          Part A
A proton orbits a long charged wire, making $1.40 \times 10^6$ revolutions per second. The radius of the orbit is $2.00$ cm.
What is the wire's linear charge density?
Express your answer in nanocoulombs per meter.
View Available Hint(s)
$\lambda = -23.42$ nC/m
Submit Previous Answers
Incorrect; Try Again; 5 attempts remaining
Provide Feedback

part a a proton orbits a long charged wire making 140 times 106 revolutions per second the radius of the orbit is 200 cm what is the wires linear charge density express your answer in nanoco 53154

Added by Samuel H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Mayukh Banik

08/29/2020

Step 1

40 \times 10^6$ revolutions/second - Radius of the orbit, $r = 2.00$ cm $= 0.02$ m - Charge of a proton, $q_p = 1.602 \times 10^{-19}$ C - Mass of a proton, $m_p = 1.672 \times 10^{-27}$ kg - Coulomb's constant, $k = 8.9875 \times 10^9$ N$\cdot$m$^2$/C$^2$ Show more…

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Part A A proton orbits a long charged wire, making $1.40 \times 10^6$ revolutions per second. The radius of the orbit is $2.00$ cm. What is the wire's linear charge density? Express your answer in nanocoulombs per meter. View Available Hint(s) $\lambda = -23.42$ nC/m Submit Previous Answers Incorrect; Try Again; 5 attempts remaining Provide Feedback