Question

BF3(g) + NH3 (g) ? F3BNH3 (9) For the above reaction, the following data were measured: Initial Rate Experiment [BF3] (M) [NH3] (M) (M/S) 1 0.250 0.250 0.2130 2 0.250 0.125 0.1065 3 0.200 0.100 0.0682 4 0.350 0.100 0.1193 5 0.175 0.100 0.0596 Part A What is the rate law for the reaction? rate = k[BF3]2 [NH3] rate = k[BF3] [NH3] rate = k[BF3] [NH3]2 rate = k[BF3]2 [NH3]2 Submit Previous Answers Request Answer

          BF3(g) + NH3 (g) ? F3BNH3 (9)
For the above reaction, the following data were measured:
Initial Rate
Experiment [BF3] (M) [NH3] (M) (M/S)
1
0.250
0.250
0.2130
2
0.250
0.125
0.1065
3
0.200
0.100
0.0682
4
0.350
0.100
0.1193
5
0.175
0.100
0.0596
Part A
What is the rate law for the reaction?
rate = k[BF3]2 [NH3]
rate = k[BF3] [NH3]
rate = k[BF3] [NH3]2
rate = k[BF3]2 [NH3]2
Submit
Previous Answers Request Answer

BF3(g) + NH3 (g) ? F3BNH3 (9)
For the above reaction, the following data were measured:
Initial Rate
Experiment [BF3] (M) [NH3] (M) (M/S)
1
0.250
0.250
0.2130
2
0.250
0.125
0.1065
3
0.200
0.100
0.0682
4
0.350
0.100
0.1193
5
0.175
0.100
0.0596
Part A
What is the rate law for the reaction?
rate = k[BF3]2 [NH3]
rate = k[BF3] [NH3]
rate = k[BF3] [NH3]2
rate = k[BF3]2 [NH3]2
Submit
Previous Answers Request Answer

Added by Pamela P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Thanks for your feedback!

Part A BF3(g) + NH3(g) -> FBNH3(g) For the above reaction, the following data were measured: Experiment [BF3](M) [NH3](M) Initial Rate (M/s) 1 0.250 0.250 0.2130 2 0.250 0.125 0.1065 3 0.200 0.100 0.0682 4 0.350 0.100 0.1193 5 0.175 0.100 0.0596 What is the rate law for the reaction? O rate = k[BF3]2[NH3] O rate = k[BF][NH3] O rate = k[BF][NH3]2 O rate = k[BF]2[NH3]2