00:01
Hello students, in this question first we see the direction of current.
00:05
So here is i, here is i and in this direction i1 and in this i minus i1.
00:18
So now here we see applying kirchop's law in the loop in the loop a, b, c.
00:38
C .f .f .f .f .f .f .f.
00:41
We can write 17 .6i plus 34 .5i1 minus 6 is equal to 0.
00:55
This is the equation 1.
00:57
Now applying catch off here in the loop, fcda, we get minus 34 .5i1 plus 21 .3 i .5 i .m.
01:17
Minus i1 plus 9 is equal to 0.
01:24
So minus 34 .5 i1 plus 21 .3i1 minus 21 .3i minus 21 .3 i .1 plus 9 is equal to 0.
01:42
So now here we can write 21 .3i minus 55 .8 i1 plus 9 is equal to 0.
01:56
This is the equation number 2.
01:59
Now, equation 1 multiplied by 55 .8 plus equation 2 multiplied by 34 .5...