Part A Determine the shear in the beam as a function of $x$, for $0 \le x \le 18$ ft, where $x$ is in feet. $V = ( - \frac{1}{6} x^2 + 15.75 ) \text{ k}$ $V = ( - \frac{1}{12} x^2 + 15.75 ) \text{ k}$ $V = ( - \frac{1}{6} x^2 + 11.25 ) \text{ k}$ $V = ( - \frac{1}{12} x^2 + 11.25 ) \text{ k}$
Added by George G.
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- The beam has a triangular distributed load with a maximum intensity of 3 k/ft at the right end. Show more…
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