00:01
Here we are given a variable resistance which is represented by r0 which is connected across the terminals a and b which are shown here in the circuit where we are given the value of vs that is equals to 210 volt and the value of r is given that is equals to 5 .6 kilo ohm.
00:17
We have to find out the percentage of the total power developed in the circuit.
00:22
So from here from the circuit we can say that the value of i is equals to 350 minus of v of i which is divided by 2000.
00:31
So here we are using the kirchhoff's law.
00:35
So from the kirchhoff's law at the node 1 we can say that v1 minus 350 which is divided by the 2000 plus v1 divided by the 2000 plus v1 minus v2 divided by the 2000 become equals to minus of 0 .2 of i delta.
00:52
Solving the term we get the value of equation that become equals to 2 .8 of v1 minus v2 become equals to 280.
00:58
Let's say this is the equation number 1.
01:00
Now we are applying the kirchhoff's law at the node 2 again that is v2 divided by 1866 .67 plus v2 divided by 5600 plus v2 minus v1 which is divided by the 2000 become equals to 0 .2 of i of delta.
01:18
Further simplifying this equation we get the value that is v1 of 0 .0004 plus v2 of 1 .214 which is multiplied by the 10 raised to the power minus 3 become equals to 0 .035...