Part A What is the pH of a solution prepared by mixing 30.00 mL of 0.10 M CH3CO2H with 30.00 mL of 0.030 M CH3CO2K? Assume that the volume of the solutions are additive and that Ka = 1.8 !! 10?5 for CH3CO2H. 4.75 5.27 2.87 4.22
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First, we need to find the moles of CH3CO2H and CH3CO2K in the solution. Moles of CH3CO2H = Molarity × Volume = 0.10 M × 0.030 L = 0.0030 mol Moles of CH3CO2K = Molarity × Volume = 0.030 M × 0.030 L = 0.0009 mol Show more…
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