What is the pH of a solution prepared by mixing 25.00 mL of 0.10 M CH3COOH with 25.00 mL of 0.050 M CH3COONa? Assume that the volume of the solutions are additive and that Ka = 1.8 x 10-5 for CH3COOH.
Added by Daniela C.
Step 1
- CH3COOH: 0.10 M * 25.00 mL / 50.00 mL = 0.050 M - CH3COONa: 0.050 M Show more…
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