Part A What is the strength of an electric field that a 0.010 C negative charge experiences 0.8 mm from a 0.20 C positive charge? 7 x 10^16 N/C 1.4 x 10^15 N/C 2.8 x 10^15 N/C 2.8 x 10^16 N/C
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So, 0.8 mm = 0.0008 m. The formula for the electric field (E) created by a point charge (q) at a distance (r) is given by Coulomb's law: E = k*q/r^2 where k is Coulomb's constant, which is approximately 9.0 x 10^9 N*m^2/C^2. Show more…
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