Question

b) How many grams of iron is 6.88 x 10?² mol of Fe? 58. How many atoms are present in 0.470 mol of uranium? that relates mol and atoms: 1 mol of atoms = 6.02 x 10²³ atoms

          b) How many grams of iron is 6.88 x 10?² mol of Fe?
58. How many atoms are present in 0.470 mol of uranium?
that relates mol and atoms: 1 mol of atoms = 6.02 x 10²³ atoms

Added by Peter L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Keerti J

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We are given that there are 6.88 x 10^2 mol of Fe. Show more…

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Part B: Not sure where does the exponent go? How do I end up with just the grams? I am trying to understand how to get rid of that exponent. Please show me step by step. Thank you. 01. Who: 58. How many atoms are present in 0.470 mol of uranium? b) How many grams of iron is 6.88 x 10^2 mol of Fe? 160 Co. 86 x 10^-2 mol of R x 1 mol of R = 55.859 grams