PART E: Final Challenge Cut a piece of aluminum foil to the right size so that it will contain \( 4.5 \times 10^{22} \) atoms. Show this to your instructor to be sure you took the right amount. To help, you will need to know that aluminum has an average mass of \( 26.98 \mathrm{~g} / \mathrm{mol} \), and that Avogadro' number of atoms is \( 6.02 \times 10^{23} \) atoms/mole. Calculations: \[ 26.98 \mathrm{~g} / \mathrm{mol} \] Put \( 8.3 \times 10^{23} \) molecules of sand in a beaker. Show this to your instructor to b you took the right amount. Sand has a molecular formula of \( \mathrm{SiO}_{2} \), the averag Si is \( 28.09 \mathrm{~g} / \mathrm{mol} \), the average mass of \( O \) is \( 16.00 \mathrm{~g} / \mathrm{mol} \), and Avogadro's nur molecules is \( 6.02 \times 10^{23} \) molecules/mole. Calculations:
Added by Xaviera R.
Close
Step 1
### For Aluminum Foil ** Show more…
Show all steps
Your feedback will help us improve your experience
John Nicolle and 73 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Determine the volume of one atom of aluminum. Determine the number of atoms of aluminum in the foil sample. Calculate Avogadro’s number. Trial: Length of Aluminum Foil: 28 cm Width of Aluminum Foil: 10 cm Area of Aluminum Foil: 28 cm x 10 cm = 280 cm^2 Mass of Aluminum Foil: 1.06 g Density of Aluminum: 2.70 g/cm^3 Atomic Mass of Aluminum: 26.98 g/mol Atomic Radius of Aluminum (picometer = 10^-12 meters): 10,143 pm Number of Layers of Aluminum Atoms: 690 Number of Aluminum Atoms: 2.36 x 10^22 atoms Avogadro’s Number: Number of Aluminum Atoms / Moles of Aluminum = 6.022 x 10^23
Shaiju T.
Part 2. Avogadro’s constant, molar ratio and mass The mole (mol) is a measure of the number of particles (e.g. atoms or molecules) in a given substance. One mole is equal to 6.02214179 × 10^23 particles (usually four sig figs is enough precision). This very large number is called Avogadro’s constant. The number of moles of a given substance can be calculated with the atomic masses of elements (see periodic table on the last page). For example, one mole of nitrogen gas contains 6.02214179 × 10^23 molecules of N2 and weighs 28 grams. The mass of a mole of substance is called its molar mass. The molar mass of an element is the element’s atomic weight in grams/mole. For example, per mole of CO2, there is 1 mole of carbon and 2 moles of oxygen. - How many atoms are there in 5 g of silicon (Si)? - How many atoms are contained in 1 g of salt (NaCl)? - What is the ratio of the atomic mass of oxygen atoms to carbon atoms in carbon dioxide (CO2)?
Yogesh R.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Watch the video solution with this free unlock.
EMAIL
PASSWORD