00:01
Suppose f of x equals 7 over x.
00:02
Now for the first part of this problem, we want to find f prime of 2 using limit definition of derivatives.
00:09
Now, f .m.
00:11
Of 2, this is equal to the limit as h approaches 0 of f of 2 plus h minus f of 2 all over h.
00:21
So then from here we should get limit as h approach 0 of 7 over 2 plus h minus 7.
00:30
Over 2, this times the reciprocal of h, which is 1 over h.
00:35
Simplifying further, we get limit as h approach 0 of 7 times 2 minus 7 times 2 plus h all over 2 plus h times 2, this times 1 over h.
00:49
And then from here we should get limit as h approaches 0 of 14 minus 14 minus 7h all over 2 plus h times 2 plus h times.
01:00
2, this times 1 over h.
01:03
From here we can get rid of 14 and negative 14 and we're left with limit as h approaches 0 of negative 7h all over 2 plus h times 2 times 1 over h and we can get rid of the h and from here we should get limit as h approaches 0 of negative 7 over 2 plus h times 2.
01:30
Evaluating the limit we should get negative 7 over 2 plus 0 times 2 that's equal to negative 7 over 4.
01:38
So this is the value of the derivative of f evaluated at 2.
01:44
And for the second part we want to find the derivative of f of x using limit definition...