Question

The equation of a hyperbola is 9y^2 - 16x^2 - 18y - 64x + 89 = 0. a) Find the center, vertices, transverse axis, and asymptotes of the hyperbola. b) Use the vertices and the asymptotes to graph the hyperbola. a) The center of the hyperbola is (-2, 1). (Type an ordered pair.) The vertices are (Type an ordered pair. Use a comma to separate answers as needed.)

          The equation of a hyperbola is 9y^2 - 16x^2 - 18y - 64x + 89 = 0.
a) Find the center, vertices, transverse axis, and asymptotes of the hyperbola.
b) Use the vertices and the asymptotes to graph the hyperbola.
a) The center of the hyperbola is (-2, 1). (Type an ordered pair.)
The vertices are 
(Type an ordered pair. Use a comma to separate answers as needed.)

The equation of a hyperbola is 9y^2 - 16x^2 - 18y - 64x + 89 = 0.
a) Find the center, vertices, transverse axis, and asymptotes of the hyperbola.
b) Use the vertices and the asymptotes to graph the hyperbola.
a) The center of the hyperbola is (-2, 1). (Type an ordered pair.)
The vertices are
(Type an ordered pair. Use a comma to separate answers as needed.)

Added by Timothy G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Khushbu Rani

Step 1

The vertices are given as (0, 1) and (-4, 1), which also match the equation. To find the transverse axis, we need to determine the distance between the vertices. In this case, the distance is 4 units, so the transverse axis is horizontal. To find the asymptotes, Show more…

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The equation of a hyperbola is 9y^2 - 162 - 18y - 64x + 89 = 0. a) Find the center, vertices, transverse axis, and asymptotes of the hyperbola. b) Use the vertices and the asymptotes to graph the hyperbola. a) The center of the hyperbola is (-2, 1). The vertices are (0, 1) and (-4, 1).