Question

Partial Differential Equations: The following convection-diffusion-decay equation appears in many physical applications: ut = Duxx - cux - gu Show that this equation can be transformed into a heat equation for w(x,t) by applying the transformation u(x,t) = w(x,t)e^(ax-bt) HINT: You will only obtain a heat equation for w(x,t) with an appropriate choice for the constants a and b in terms of the constants D, c, and g. Determine the choice for a and b that produces a heat equation for w(x,t).

          Partial Differential Equations:
The following convection-diffusion-decay equation appears in many physical applications:
ut = Duxx - cux - gu
Show that this equation can be transformed into a heat equation for w(x,t) by applying the transformation
u(x,t) = w(x,t)e^(ax-bt)
HINT: You will only obtain a heat equation for w(x,t) with an appropriate choice for the constants a and b in terms of the constants D, c, and g. Determine the choice for a and b that produces a heat equation for w(x,t).
        
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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Partial Differential Equations: The following convection-diffusion-decay equation appears in many physical applications: ut = Duxx - cux - gu Show that this equation can be transformed into a heat equation for w(x,t) by applying the transformation u(x,t) = w(x,t)e^(ax-bt) HINT: You will only obtain a heat equation for w(x,t) with an appropriate choice for the constants a and b in terms of the constants D, c, and g. Determine the choice for a and b that produces a heat equation for w(x,t).
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Transcript

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00:01 In this question we have our experimental vehicle for which we are making our graph here and for making the graph.
00:11 First of all we will take in our first part of the question, y is equal to v of t.
00:18 So our equation will be 0 .0008.
00:24 T -q was 0 .0755 t squared minus 0 .123 .000 .000 t squared minus 0 .123.
00:33 28 t minus 0 .0476.
00:39 So this is a solution for the given question.
00:43 We can read this from the graph.
00:47 As you can see, here is the graph and this is our equation.
00:51 And we have made this graph from the xl, msxl, by using our formula.
00:59 So this is the graph and here we have our modes for the velocity versus time graph.
01:05 On x -exes we have plotted time and y -axis we have plotted velocity.
01:10 So for part b, in the part b, you need to find the image...
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