A particle is released as part of an experiment. Its speed t seconds after release is given by v(t) = -0.5t^2 + 2t, where v(t) is in meters per second. a) How far does the particle travel during the first 2 sec? b) How far does it travel during the second 2 sec? a) The particle travels [ ] meters in the first 2 sec. (Round to two decimal places as needed.) b) The particle travels [ ] meters in the second 2 sec. (Round to two decimal places as needed.)
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5t^2 + 512t \right]_{0}^{2} \] \[ = (-0.5(2)^2 + 512(2)) - (-0.5(0)^2 + 512(0)) \] \[ = (-2 + 1024) - (0) \] \[ = 1022 \text{ meters} \] ** Show more…
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