Question

10. p(B) A) 0.16 B) 0.46 C) 0.67 D) 0.89 Q.3 (2 points) : The following Table represent the probability mass function: X 1 2 3 4 P(X = x) 0.25 0.35 0.30 0.10 Use this information to answer questions (11-12): 11. p(X > 2) is A) 0.40 B) 0.25 C) 0.75 D) 0 12. p(1 < X <= 4) is : A) 0.50 B) 0.65 C) 0.75 D) 0 Q.5 (3 points): The following circuit operates if and only if there is a path of functional devices from left to right. Assume devices fail independently and that the probability of failure of each device is as shown. What is the probability that the circuit operates? Q.6 (2 points): Customers are used to evaluate preliminary product designs. In the past, 95% of highly successful products received good reviews, 60% of moderately successful products received good reviews, and 10% of poor products received good reviews. In addition, 40% of products have been highly successful, 35% have been moderately successful, and 25% have been poor products. (a) What is the probability that a product attains a good review? (b) If a new design attains a good review, what is the probability that it will be a highly successful product

          10. p(B)
A) 0.16 B) 0.46 C) 0.67 D) 0.89
Q.3 (2 points) : The following Table represent the probability mass function:
X 1 2 3 4
P(X = x) 0.25 0.35 0.30 0.10
Use this information to answer questions (11-12):
11. p(X > 2) is
A) 0.40 B) 0.25 C) 0.75 D) 0
12. p(1 < X <= 4) is :
A) 0.50 B) 0.65 C) 0.75 D) 0
Q.5 (3 points): The following circuit operates if and only if there is a path of functional devices from left to right. Assume devices fail independently and that the probability of failure of each device is as shown. What is the probability that the circuit operates?
Q.6 (2 points):
Customers are used to evaluate preliminary product designs. In the past, 95% of highly successful products received good reviews, 60% of moderately successful products received good reviews, and 10% of poor products received good reviews. In addition, 40% of products have been highly successful, 35% have been moderately successful, and 25% have been poor products.
(a) What is the probability that a product attains a good review?
(b) If a new design attains a good review, what is the probability that it will be a highly successful product

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10. p(B)
A) 0.16 B) 0.46 C) 0.67 D) 0.89
Q.3 (2 points) : The following Table represent the probability mass function:
X 1 2 3 4
P(X = x) 0.25 0.35 0.30 0.10
Use this information to answer questions (11-12):
11. p(X > 2) is
A) 0.40 B) 0.25 C) 0.75 D) 0
12. p(1 < X <= 4) is :
A) 0.50 B) 0.65 C) 0.75 D) 0
Q.5 (3 points): The following circuit operates if and only if there is a path of functional devices from left to right. Assume devices fail independently and that the probability of failure of each device is as shown. What is the probability that the circuit operates?
Q.6 (2 points):
Customers are used to evaluate preliminary product designs. In the past, 95% of highly successful products received good reviews, 60% of moderately successful products received good reviews, and 10% of poor products received good reviews. In addition, 40% of products have been highly successful, 35% have been moderately successful, and 25% have been poor products.
(a) What is the probability that a product attains a good review?
(b) If a new design attains a good review, what is the probability that it will be a highly successful product

Added by Ronald B.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Madhur L

01/17/2023

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95 P(moderately successful) = 0.60 P(poor) = 0.25 Show more…

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10. p(B) A) 0.16 B) 0.46 C) 0.67 D) 0.89 Q.3 (2 points) : The following Table represent the probability mass function: X 1 2 3 4 P(X = x) 0.25 0.35 0.30 0.10 Use this information to answer questions (11-12): 11. p(X > 2) is A) 0.40 B) 0.25 C) 0.75 D) 0 12. p(1 < X <= 4) is : A) 0.50 B) 0.65 C) 0.75 D) 0 Q.5 (3 points): The following circuit operates if and only if there is a path of functional devices from left to right. Assume devices fail independently and that the probability of failure of each device is as shown. What is the probability that the circuit operates? Q.6 (2 points): Customers are used to evaluate preliminary product designs. In the past, 95% of highly successful products received good reviews, 60% of moderately successful products received good reviews, and 10% of poor products received good reviews. In addition, 40% of products have been highly successful, 35% have been moderately successful, and 25% have been poor products. (a) What is the probability that a product attains a good review? (b) If a new design attains a good review, what is the probability that it will be a highly successful product

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Transcript

00:01 Hi, from the question given that for the 11th problem, x 1, 2, 3, 4 and the probability mass function, probability of x is equal to x is 0 .25, 0 .35, 0 .30, 0 .10.

00:25 Here we need to find probability of x greater than 2.

00:29 So, this can be written as probability of x is equal to 3 plus probability of x is equal to 4.

00:38 So, this is equal to 0 .30 plus 0 .10.

00:44 So, this is equal to 0 .40.

00:46 Hence, we conclude that the correct option is option a.

00:53 And we need to calculate probability of 1 is less than x is less than or equal to 4.

01:00 So this can be written as 1 is not included but 4 is included.

01:04 So probability of x is equal to 2 plus probability of x is equal to 3 plus probability of x is equal to 4.

01:13 So this can be written as 0 .35 plus 0 .30 plus 0 .10.

01:21 So this can be written as probability will be 0 .75.

01:26 And so we conclude that the correct option is option.

01:31 C.

01:33 Now let us move on to the next part.

01:35 So, in question number five, we need to calculate the probability of the circuit operates.

01:41 Here, the failure of the devices given here, that is, this is x1, x2, x3, x4, x5, x6.

01:54 So here we need to find the probability of the circuit operates.

01:57 First, we need to find that this is, let us assume that this will be path one and this will be path 2.

02:03 So probability of path 1 failure will be equal to probability of x1 or x2 or x3...

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