We can see that the 6 Ω and 3 Ω resistors are connected in parallel, and their equivalent resistance can be found using the formula:
$$\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2}$$
Plugging in the values, we get:
$$\frac{1}{R_{eq}} = \frac{1}{6} +
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