00:01
In this question there are three parts.
00:05
So here we have the first part as it is given that x squared divided by 3x negative 3 on the interval negative 1 to 1.
00:27
So here we need to find the critical value.
00:37
So for that we evaluate.
00:41
F -dash -x.
00:43
So here this is actually f of x.
00:46
So f -dash -x will be evaluated as by applying the quotient rule.
00:53
Here we evaluate the derivative as 3x negative 3 and a square of it.
00:59
Now we take the derivative of x squared.
01:01
It will be 2x and 3x negative 3 will be as it is negative x square.
01:07
Here the derivative of this is 6.
01:10
Further it will be written as sorry.
01:14
Here we have 3.
01:16
Now on solving it, here we have 6x square negative 6x negative 3x square which is divided by 3x negative 3x negative 3 and a square of it.
01:31
Now further here to evaluate the critical value we put f -x2b equals to 0.
01:38
That is here we have 6x square negative 6x negative 6x negative 3x square which is divided by 3x negative 3 and a square of it to be equals to 0...