Phenylalanine 2.2 9.3 Tyrosine 2.2 9.2 10.5 Tryptophan 2.5 9.4 Lysine 2.2 9.1 10.5 Arginine 1.8 9.0 12.5 Histidine 1.8 9.3 6.0 Aspartate 2.0 9.9 3.9 Glutamate 2.1 9.5 4.1 Which form of lysine will exist at some point during the titration? a form in which the carboxyl group is protonated while the amino group and the R-amino group are both deprotonated a form in which the amino group is protonated while the carboxyl group and the R-amino group are both deprotonated a form in which the amino group is deprotonated while the carboxyl group and the R-amino group are both protonated a form in which the carboxyl group is deprotonated while the amino group and the R-amino group are both protonated
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2) - Alpha amino group (pKa = 9.1) - Side chain (R group) (pKa = 10.5) ** Show more…
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PROTEIN AMINO ACID SEQUENCE 1 Methionine — Threonine — Cystine — Glycine 2 Methionine — Valine — Proline — Lysine 3 Methionine — Glycine — Alanine — Serine 4 Methionine — Arginine — Phenylalanine — Isoleucine Part II 1. In the second part of the lesson, you will draw the chemical structure of each amino acid in the space provided below. Use the handout to complete this exercise. 2. To create a protein the amino acids must form a peptide bond between each amino acid. REMEMBER: A peptide bond is a bond between the hydroxyl (OH⁻) from the carboxyl group (COOH) from one amino acid and the hydrogen (H⁺) from the amine group (NH₂) from another amino acid. This bond forms a water molecule (OH⁻ + H⁺ = H₂O or HOH). To complete the peptide, bond the water molecule must be removed through a process called dehydration synthesis. To reverse the process and break the bond, you add a water molecule through a process called hydrolysis.
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Exercise A: Amino Acid Functional Groups Figure 1 below shows one of the 20 amino acids that make up proteins. Recall that carbon can form four covalent bonds. Amino acids consist of a central carbon, called the α-carbon, that is bonded to four different chemical groups. H₃N⁺ C-C-C=O H Figure 1. Structure of an amino acid Answer the below questions in your own document: On the amino acid shown in Figure 1, label the α-carbon: The α-carbon of each of the 20 amino acids is bonded to one hydrogen atom, one amino group, one carboxyl group, and one R group (more on that below): You should recognize the amino and carboxyl groups from our discussion of functional groups in organic molecules. Circle and label the amino group and the carboxyl group in Figure 1. Note: our goal in this question, and in similar questions throughout this lab, is for you to be able to identify specific structures. You can do this circling/labeling in whatever way is easiest for you: You might want to draw the structures on a piece of paper; or use a computer program (like PowerPoint, Photoshop, Paint, Preview, etc.) to draw on these images. Whatever is easiest for you! The last bond an α-carbon in an amino acid makes is to an R group or side-chain. Circle and label the R group in Figure 1. The next page of this handout shows the structures of all 20 amino acids (Figure 2). They are categorized into 4 chemical groups: nonpolar, uncharged polar, acidic, and basic. Using the three groups you identified in Figure 1 as a reference, what is the only thing that is different about each of the 20 amino acids? Look at the amino acids in each of the four groups and compare them to the ones in the other groups. Figure out rules that describe what the members of each group.
Alpha amino acids are organic acid molecules that also happen to contain an amino group $\left(-\mathrm{NH}_{2}\right)$ on the second carbon atom of the acid’s chain. Proteins are condensation polymers of such alpha amino acids. The reaction by which the long chain of the protein forms is very similar to the reaction by which nylon forms, resulting in the formation of the linkage GRAPH CANNOT COPY which is called an “amide” (or “peptide”) linkage. Show how the following two amino acids could react with each other to produce an amide linkage, resulting in the formation of a dimer (a “dipeptide”). GRAPH CANNOT COPY How could this dipeptide then go on to react with additional amino acids to form a polypeptide?
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