Question

2 m Plan View of Flat Plate m V = 3402- s ??? = 1.7894x10-5 kg ms 20 m P? = 1.01x10-5 N m2 T? = 288 K Use the plots on the next page to compute the following for laminar flow at the above conditions over a flat plate with the above dimensions: 1. Local shear stress 0.5 m downstream of the leading edge. Assume the plate is insulated. 2. Skin-friction drag for the whole plate. Assume air flows over both top and bottom surfaces, and that the plate is insulated. 3. Heat-transfer rate at quarter chord assuming a wall temperature of 288 K $\frac{T_w}{T_?}$ = 0.25 0.7 $\frac{T_w}{T_?}$ = 1.00 $\frac{T_w}{T_?}$ = 2.00 0.664 0.6 0.5 $\frac{C_f\sqrt{Re_x}}{2}$ = 4.00 $\frac{C_f\sqrt{Re_x}}{2}$ 0.4 $\frac{T_w}{T_?}$ = 6.00 0.3 Insulated plate 0.2 0.1 0 0 2 4 6 8 10 12 14 16 18 20 $\frac{T_w}{T_?}$ = 0.25 0.5 $\frac{T_w}{T_?}$ = 1.00 $\frac{T_w}{T_?}$ = 2.00 0.4 $\frac{C_f\sqrt{Re_x}}{2}$ = 4.00 $\frac{C_f\sqrt{Re_x}}{2}$ 0.3 $\frac{T_w}{T_?}$ = 6.00 0.2 Insulated plate 0.1 0 0 2 4 6 8 10 12 14 16 18 20 Mx Mx

          2 m
Plan View of Flat Plate
m
V = 3402-
s
??? = 1.7894x10-5 kg
ms
20 m
P? = 1.01x10-5 N
m2
T? = 288 K
Use the plots on the next page to compute the following for laminar flow at the above conditions over a flat plate
with the above dimensions:
1. Local shear stress 0.5 m downstream of the leading edge. Assume the plate is insulated.
2. Skin-friction drag for the whole plate. Assume air flows over both top and bottom surfaces, and that the plate is
insulated.
3. Heat-transfer rate at quarter chord assuming a wall temperature of 288 K
$\frac{T_w}{T_?}$ = 0.25
0.7
$\frac{T_w}{T_?}$ = 1.00
$\frac{T_w}{T_?}$ = 2.00
0.664
0.6
0.5
$\frac{C_f\sqrt{Re_x}}{2}$ = 4.00
$\frac{C_f\sqrt{Re_x}}{2}$
0.4
$\frac{T_w}{T_?}$ = 6.00
0.3
Insulated plate
0.2
0.1
0
0
2
4
6
8
10
12
14
16
18
20
$\frac{T_w}{T_?}$ = 0.25
0.5
$\frac{T_w}{T_?}$ = 1.00
$\frac{T_w}{T_?}$ = 2.00
0.4
$\frac{C_f\sqrt{Re_x}}{2}$ = 4.00
$\frac{C_f\sqrt{Re_x}}{2}$
0.3
$\frac{T_w}{T_?}$ = 6.00
0.2
Insulated plate
0.1
0
0
2
4
6
8
10
12
14
16
18
20
Mx
Mx
        
Show more…
2 m
Plan View of Flat Plate
m
V = 3402-
s
??? = 1.7894x10-5 kg
ms
20 m
P? = 1.01x10-5 N
m2
T? = 288 K
Use the plots on the next page to compute the following for laminar flow at the above conditions over a flat plate
with the above dimensions:
1. Local shear stress 0.5 m downstream of the leading edge. Assume the plate is insulated.
2. Skin-friction drag for the whole plate. Assume air flows over both top and bottom surfaces, and that the plate is
insulated.
3. Heat-transfer rate at quarter chord assuming a wall temperature of 288 K
(Tw)/(T?) = 0.25
0.7
(Tw)/(T?) = 1.00
(Tw)/(T?) = 2.00
0.664
0.6
0.5
(Cf√(Rex))/(2) = 4.00
(Cf√(Rex))/(2)
0.4
(Tw)/(T?) = 6.00
0.3
Insulated plate
0.2
0.1
0
0
2
4
6
8
10
12
14
16
18
20
(Tw)/(T?) = 0.25
0.5
(Tw)/(T?) = 1.00
(Tw)/(T?) = 2.00
0.4
(Cf√(Rex))/(2) = 4.00
(Cf√(Rex))/(2)
0.3
(Tw)/(T?) = 6.00
0.2
Insulated plate
0.1
0
0
2
4
6
8
10
12
14
16
18
20
Mx
Mx

Added by Amanda K.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Title: Plan View of Flat Plate 2m m V = 3402 S 20m P = 1.01 x 10^5 N T = 288 K ms Use the plots on the next page to compute the following for laminar flow at the above conditions over a flat plate with the above dimensions: 1. Local shear stress 0.5 m downstream of the leading edge. Assume the plate is insulated. 2. Skin-friction drag for the whole plate. Assume air flows over both top and bottom surfaces, and that the plate is insulated. 3. Heat-transfer rate at quarter chord assuming a wall temperature of 288 K. T = 0.25 T, T, 1.00 T, 2.00 T 0.7 0.664 0.6 T T = 1.00 T, 0.5 T = 2.00 T. 0.4 0.5 T, 4.00 T, VRe, 0.41 T = 6.00 T. 0.3 0.3 CHURe, Te 0.2 T = 6.00 T. Insulated plate Insulated plate 0.1 10 12 16 M M
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Transcript

-
00:01 At this question we have to find the del, the displacement and the chesteros, t -sq -w at x equal l, and find a drag force at the portion 0 .5 and 2l.
00:18 So first, from the basic equation of cf and del over x.
00:25 We can have that if the random number is ul over 2.
00:31 0 .05 10 to 0 .10 to power 6 for this one.
00:41 You can have that double out is l time 0 .382 divided by number to power of 1 over 5.
00:54 And we can have that tt that taw is 1 over 2 row u square time 0 .0 .0 .0 .0 .0 .0 .2 0 .2 0 .2 0.
01:02 9 -fold right by the rainbow number to the power 1 over 5...
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