00:01
Hello students, in this question the plant parents have the genotype, one parent has the genotype this which is crossed with the parent which has genotype this.
00:24
Now we need to calculate the probability of offspring having this genotype.
00:33
So for this we need to calculate the individual probability for each gene.
00:40
So in the first case if we cross a with a, then in this scenario there are four kinds of offsprings a, this and this and this as this allele will cross with this leading to this genotype, this allele will cross with the a and lead to this similarly for these two.
01:22
So in this case the probability of getting both the allele as the dominant one, the probability is half because out of the four offspring, two offspring have the dominant homozygous condition.
01:40
So this is the dominant homozygous genotype and the probability of getting this is 1 by in the next case if we cross bb with bb, then the parents are bb, the other offspring is bb, bb and bb.
02:23
So the probability of getting the dominant homozygous offspring in this case is 1 by 4 as out of the four offspring only one offspring will have the dominant homozygous condition...