Question

Let f(x) = \begin{cases} -x + b, & \text{if } x < -3 \\ 4, & \text{if } x = -3 \\ \frac{-12}{x - b} + 1, & \text{if } x > -3 \text{ (and } x \neq b) \end{cases} a) For what value(s) of b does f have a removable\ discontinuity at -3?\nb) For what value(s) of b does f have a jump\ discontinuity at -3. Write your answer in interval notation\ using $\cup$ for union.

          Let
f(x) = \begin{cases} -x + b, & \text{if } x < -3 \\ 4, & \text{if } x = -3 \\ \frac{-12}{x - b} + 1, & \text{if } x > -3 \text{ (and } x \neq b) \end{cases}
a) For what value(s) of b does f have a removable\ discontinuity at -3?\nb) For what value(s) of b does f have a jump\ discontinuity at -3. Write your answer in interval notation\ using $\cup$ for union.

Let
f(x) = -x + b, if x < -3
4, if x = -3
(-12)/(x - b) + 1, if x > -3 (and x ≠b)
a) For what value(s) of b does f have a removable discontinuity at -3?) For what value(s) of b does f have a jump discontinuity at -3. Write your answer in interval notation using ∪ for union.

Added by Nicholas S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Andrew Davis

02/01/2022

Step 1

To do this, we can subtract b from both sides of the equation: x + b - b = c - b Show more…

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Thanks for your feedback!

Please answer a & b and help explain the answers step by step :) a) Let x + b = c. Solve for x. b) For what value(s) of b does 8 have a jump using √ for union? Explanation: a) The equation x + b = c can be solved for x by subtracting b from both sides of the equation: x + b - b = c - b x = c - b b) The question is asking for what value(s) of b does 8 have a jump using the square root symbol (√) for union. However, the given text is not clear and contains OCR errors, making it difficult to understand the exact question being asked.