```
A-----B
| |
X-----C
| |
Y-----D
| |
Z-----E
```
Since X is the midpoint of AB, we have $\overrightarrow{AX} = \overrightarrow{XB}$. Also, since Y and Z trisect CD, we have $\overrightarrow{CY} = \overrightarrow{YD} = \overrightarrow{DZ}$.
Now,
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