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Please answer ASAP, correctly please. 8 3 Figure 1 reuse system was employed (assume K=3)? Justify your answer. example of channel allocation amongst the cells. c) Give a reason why dynamic frequency re-use systems are not more commonly used?

          Please answer ASAP, correctly please.
8
3
Figure 1
reuse system was employed (assume K=3)? Justify your answer.
example of channel allocation amongst the cells. c) Give a reason why dynamic frequency re-use systems are not more commonly used?
        
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please answer asap correctly please 8 3 figure 1 reuse system was employed assume k3 justify your answer example of channel allocation amongst the cells c give a reason why dynamic frequency 63121

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Please answer ASAP, correctly please. 8 3 Figure 1 reuse system was employed (assume K=3)? Justify your answer. example of channel allocation amongst the cells. c) Give a reason why dynamic frequency re-use systems are not more commonly used?
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Problem 4 (12 marks): Consider a cellular system comprising 32 cells (figure below, left) with a cell radius of 1.6km, a total frequency bandwidth that supports 336 traffic channels, and a reuse factor of N = 7. a) Find the exact geographical area covered by the system, the number of channels per cell, and the number of concurrent calls that can be handled over the total area. b) Repeat part a) for a system comprising 128 cells with cell radius of 0.8km (figure, right). c) Briefly explain and illustrate the concepts of cell splitting and cell sectoring, which can be used to increase the number of simultaneous channels in the above systems.

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Transcript

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00:01 From this question we can start available, available bandwidth which is equal to 33 mega hertz and the next one channel bandwidth which is 25 kilo hertz and the total number of channel is 1320 channels.
00:53 So now for 12 cells reuse we have to calculate number of channels per cell.
01:21 So which is equal to number of channel is 1320 divided by 2 which we have to get 110 channels...
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