00:01
Hello everyone here in this question from the given information we know that p1 is equal to 1 and p2 is equal to 2 x p 3 is equal to p 3 is equal to minus 2 x square p4 is equals to minus 12x minus 12x plus 8x cube so we are given with these values now as for the first condition since since dim of p3 is equal to 4 and module s is equals to 4 so if f is a linear independent set, then it will span p3 and form basis of p3.
01:38
So if we check these are independents or not by taking the coefficient matrix, by taking the coefficient matrix of p1, p1, p2, p3, b4 by taking the coefficient as 1 comma x comma x square comma x cube we can check the rank of a as equals to 4 or not so the matrix a will be equals to matrix of matrix of 1 000 0 to 0 to 0 0 0 0 0 0 0 0 0 minus 2 040 minus 12 and 8 matrix close.
02:53
So we got the a as this matrix.
02:56
So operating r3 equals to r3 plus to r2 to r2, then a will be equals to matrix of 1.
03:16
Matrix of 1 ,000, 0200, 0200, 004, and 000 minus 128.
03:30
So this is the matrix of a.
03:33
So if operating r4 equals to r4 plus 3r3, then we will get the rank a equals to a matrix to matrix of 1 -0 -00 -0 -0 -2 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -8 so we got the matrix as like this for r4 equals to r4 plus 3r3 so now we can say that rank of a is equal to 4 which is equal to module s...