Solve the following problems: (10 pts each) 1. Find the force on charge Q1 = 20?C, due to charge Q2 = -300?C , where Q1 is at (0, 1, 2)m and Q2 is at (2, 0, 0)m. Also, plot the charges & the force on an xyz-plane. 2. Find the force at (0, 3, 4)m in Cartesian coordinates due to a point charge Q = 0.5?C at the origin. 3. Find the total field force at (0, 0, 5)m due to Q1 = 0.35?C at (0, 4, 0)m and Q2 = -0.55?C at (3, 0, 0)m
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Given that Q1 is located at (0, 1, 2) and Q2 is located at (2, 0, 0), the distance between them can be calculated using the formula: \[d = \sqrt{(2-0)^2 + (1-0)^2 + (2-0)^2} = \sqrt{4 + 1 + 4} = \sqrt{9} = 3 \text{ meters}\] Show more…
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