(a) Find the slope of the tangent line to the curve $y^3 - 3xy + 2x^2 = 4$ at the point $(3, 2)$.
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The given equation is y^3 - 3xy + 2x^2 = 4. To find the slope of the tangent line, we need to express y as a function of x. Rearranging the equation, we get y^3 = 3xy - 2x^2 + 4. Taking the cube root of both sides, we have y = (3xy - 2x^2 + 4)^(1/3). Show more…
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