Question

Given the following function: $g(t) = \begin{cases} -3, & t < 1 \\ t^2, & t \ge 1 \end{cases}$ We can express it as a combination of unit-step functions. From below options, select the correct answer: $g(t) = (-3 + t^2)u(t - 1)$ None of the provided choices is correct. $g(t) = -3 + (3 + t^2)u(t - 1)$ $g(t) = -3u(t - 1) + t^2u(t - 1)$ $g(t) = t^2u(t - 1)$

          Given the following function:
$g(t) = \begin{cases} -3, & t < 1 \\ t^2, & t \ge 1 \end{cases}$
We can express it as a combination of unit-step functions.
From below options, select the correct answer:
$g(t) = (-3 + t^2)u(t - 1)$
None of the provided choices is correct.
$g(t) = -3 + (3 + t^2)u(t - 1)$
$g(t) = -3u(t - 1) + t^2u(t - 1)$
$g(t) = t^2u(t - 1)$

Given the following function:
g(t) = -3, t < 1
t^2, t ≥ 1
We can express it as a combination of unit-step functions.
From below options, select the correct answer:
g(t) = (-3 + t^2)u(t - 1)
None of the provided choices is correct.
g(t) = -3 + (3 + t^2)u(t - 1)
g(t) = -3u(t - 1) + t^2u(t - 1)
g(t) = t^2u(t - 1)

Added by Carrie S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Arjun Singh

10/09/2021

Step 1

Step 1: We are given the function -3 for t less than 1 and 6 for t greater than or equal to 1. Show more…

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Please explain. Given the following function: -3, t < 1 6, t ≥ 1 We can express it as a combination of unit-step functions. From the options below, select the correct answer: A) g(t) = -3 + t^2u(t-1) B) None of the provided choices is correct C) g(t) = -3u(t-1) + t^2u(t-1) D) g(t) = tu(t-1)