(1 point) For the linear differential equation y' + 3xy = x^3e^frac-3x^22 the integrating factor

First, we need to find the integrating factor. The integrating factor for a linear differential

Question

(1 point) For the linear differential equation y' + 3xy = x^{3}e^{frac{-3x^{2}}{2}} the integrating factor is: r(x) = After multiplying both sides by the integrating factor and "unapplying" the product rule we get the new differential equation: d/dx [ ] = Integrating both sides we get the algebraic equation = Solving for y, the solution to the differential equation is y = Note: Use C as the constant. Note: You can earn partial credit on this problem.

          (1 point) For the linear differential equation y' + 3xy = x^{3}e^{frac{-3x^{2}}{2}} the integrating factor is:
r(x) =
After multiplying both sides by the integrating factor and "unapplying" the product rule we get the new differential equation:
d/dx [ ] =
Integrating both sides we get the algebraic equation
= 
Solving for y, the solution to the differential equation is
y = 
Note: Use C as the constant. 
Note: You can earn partial credit on this problem.

$(1 point) For the linear differential equation y' + 3xy = x^3e^frac-3x^22 the integrating factor is: r(x) = After multiplying both sides by the integrating factor and "unapplying" the product rule we get the new differential equation: d/dx [ ] = Integrating both sides we get the algebraic equation = Solving for y, the solution to the differential equation is y = Note: Use C as the constant. Note: You can earn partial credit on this problem.$

Added by Stacy J.

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