Use the formula for the sum of the first ( n ) terms of each geometric sequence, and then state the indicated sum. Round your answer to the nearest hundredth. [ sum_{a=1}^{11} 64 cdot 0.2^{a-1} ] [ S_{5}= ]
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Find the sum of each finite geometric series by using the formula for $S_{n}$ Check your answer by actually adding up all of the terms. Round approximate answers to four decimal places. $$\sum_{i=1}^{12} 2(1.05)^{i-1}$$
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