The average value of $f(x) = 4x^3 - 24x^2$ on the interval $[-3, 6]$ is
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To find the definite integral, we need to find the antiderivative of f(x) first. The antiderivative of 4x - 24 is 2x^2 - 24x. Now, we can find the definite integral by evaluating the antiderivative at the upper and lower limits of integration: ∫[a,b] f(x) dx = Show more…
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