Question

Make the indicated trigonometric substitution in the given algebraic expression and simplify (see Example 7). Assume that $0 < \theta < \frac{\pi}{2}$. $\frac{1}{x^2\sqrt{4 + x^2}}$, $x = 2\tan(\theta)$

          Make the indicated trigonometric substitution in the given algebraic expression and simplify (see Example 7). Assume that $0 < \theta < \frac{\pi}{2}$.
$\frac{1}{x^2\sqrt{4 + x^2}}$, $x = 2\tan(\theta)$

Make the indicated trigonometric substitution in the given algebraic expression and simplify (see Example 7). Assume that 0 < θ < (π)/(2).
(1)/(x^2√(4 + x^2)), x = 2tan(θ)

Added by Timothy C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Lauren Shelton

03/28/2022

Step 1

Step 1: Make the trigonometric substitution We are given x=2tan(θ), so we can substitute x in the expression x^2/4 + x^2 with 2tan(θ) to get (2tan(θ))^2/4 + (2tan(θ))^2. Show more…

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Please help! Make the indicated trigonometric substitution in the given algebraic expression and simplify see Example 7).Assume that 0@/2. x2/4+x2 x=2tan(0