Find the points on the curve $y = 2x^3 + 3x^2 - 12x + 1$ where the tangent line is horizontal.
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First, let's find the derivative of the function y = 2x^3 + 3x^2 + x + 1. The derivative of a polynomial function can be found by taking the derivative of each term separately. The derivative of 2x^3 is 6x^2. The derivative of 3x^2 is 6x. The derivative of x is Show more…
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