00:01
To solve this question, we need to convert x squared plus y squared into its cylindrical equivalence.
00:06
So x squared plus y squared equals r squared.
00:09
We still need to find the bounds of the r equation.
00:13
So to do that, we can look to the circle as defined.
00:16
X squared plus y squared equals r squared equals to x, but we know x equals r cos theta, which means r equals two cos theta.
00:31
So the bounds are going to be from 0 to 2 coast theta.
00:35
So now we have our whole thing.
00:37
This is going to be from 0 to 2 pi, because d theta is always defined from 0 to 2 pi unless there's a reason otherwise.
00:46
We have r going from 2 coast theta, 0 to 2 cost theta, r squared, r -d -d -theta.
01:00
So that's going to be r cubed, which is going to give us 1 .4.
01:06
R to the fourth, 2 -coz -theta, 0 -d -theta, 0 to 2 pi, 2 to the fourth, 2, 4, 8, 16, divided by 4 is going to be 4, cos to the 4th, theta, d -theta...