00:01
Okay, so for this question, you first need to figure out a.
00:05
How many grams of aluminum oxide are formed of two moles of aluminum and 0 .1 moles of iron three oxide, sorry, f .a .304 are used.
00:13
They give you the formula weights, which is excellent.
00:17
So we have two moles of aluminum.
00:22
Let's see.
00:23
The question is asking us to find the al203.
00:26
So you need to use the coefficients from the balanced equation.
00:29
There are eight aluminums formed for every four al203s used up.
00:36
I want to put the aluminum on the bottom so it cancels.
00:42
Then, since it's asking for the grams of the al203, you want to use the molecular mass of that one.
00:50
So 101 .96 grams per mole of the al203.
00:58
And then you will calculate to solve for the grams.
01:03
So you'll do two, tens, four times 101 .96, and then divided by eight, you get 101 .96, which is great, grams of al203.
01:18
So that is if you use the full amount, the two moles of aluminum.
01:22
Let's go ahead and check the other substance.
01:25
If we start with the 0 .1 moles of f .e .304 instead...