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Data: Titration #1 Titration #1 Titration #2 Titration #3 Trial A Trial B (H\(_2\)SO\(_4\) + NaOH) (HCl + Ba(OH)\(_2\)) (HCl + NaOH) Molarity of acid 0.975M 0.975M 0.775 M 0.505 M Volume of acid 100.0 mL 100.0 mL 50.0 mL 75.0 mL Volume of base used to reach 245.08 mL 240.00 mL 150.75 mL 74.95 mL the endpoint Molarity of base Molarity of Base Calculations Titration Show work NaOH: Titration #1 Trial A NaOH: Titration #1 Trial B NaOH: Titration #2 Ba(OH)\(_2\): Titration #3 Lab Questions: 1) Balance the following equations: a. # HCl + # NaOH \(\rightarrow\) # NaCl + # H\(_2\)O b. # H\(_2\)SO\(_4\) + # NaOH \(\rightarrow\) # Na\(_2\)SO\(_4\) + # H\(_2\)O c. # HCl + # Ba (OH)\(_2\)\(\rightarrow\) # BaCl\(_2\) + # H\(_2\)O

          Data:
Titration #1
Titration #1
Titration #2
Titration #3
Trial A
Trial B
(H\(_2\)SO\(_4\) + NaOH) (HCl + Ba(OH)\(_2\))
(HCl + NaOH)
Molarity of acid
0.975M
0.975M
0.775 M
0.505 M
Volume of acid
100.0 mL
100.0 mL
50.0 mL
75.0 mL
Volume of base
used to reach
245.08 mL
240.00 mL
150.75 mL
74.95 mL
the endpoint
Molarity of base
Molarity of Base Calculations
Titration
Show work
NaOH: Titration #1
Trial A
NaOH: Titration #1
Trial B
NaOH: Titration #2
Ba(OH)\(_2\): Titration #3
Lab Questions:
1) Balance the following equations:
a. # HCl + # NaOH \(\rightarrow\) # NaCl + # H\(_2\)O
b. # H\(_2\)SO\(_4\) + # NaOH \(\rightarrow\) # Na\(_2\)SO\(_4\) + # H\(_2\)O
c. # HCl + # Ba (OH)\(_2\)\(\rightarrow\) # BaCl\(_2\) + # H\(_2\)O

Data:
Titration #1
Titration #1
Titration #2
Titration #3
Trial A
Trial B
(H2SO4 + NaOH) (HCl + Ba(OH)2)
(HCl + NaOH)
Molarity of acid
0.975M
0.975M
0.775 M
0.505 M
Volume of acid
100.0 mL
100.0 mL
50.0 mL
75.0 mL
Volume of base
used to reach
245.08 mL
240.00 mL
150.75 mL
74.95 mL
the endpoint
Molarity of base
Molarity of Base Calculations
Titration
Show work
NaOH: Titration #1
Trial A
NaOH: Titration #1
Trial B
NaOH: Titration #2
Ba(OH)2: Titration #3
Lab Questions:
1) Balance the following equations:
a. # HCl + # NaOH → # NaCl + # H2O
b. # H2SO4 + # NaOH → # Na2SO4 + # H2O
c. # HCl + # Ba (OH)2→ # BaCl2 + # H2O

Added by Jose Maria B.

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