Find the following limit.\\ $\lim_{t \to 5} \left< -4t^2 - 1t + 4, \frac{t^2 - 3t - 10}{t - 5}, 2 \cdot \cos(t) \right>$\\ answer = <_, _, _>
Added by Brian W.
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The expression inside the limit is: $\frac{t^2-3t-10}{-4t^2+t+4} \cdot \frac{2\cos(t-5)}{97}$ Show more…
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