Question

3. (24 points) Provide the major product(s) for each of the following reactions. If no reaction occurs, indicate NR. KMnO$_4$ H$_3$O$^+$, heat SOCl$_2$ OH CH$_2$Cl$_2$ H$_3$O$^+$ CEN Heat CI CO$_2$H 4 1) CH$_3$CH$_2$MgBr (2 eq.) 2) H$_3$O$^+$ 1) LiAlH(O-t-bu)$_3$ 2) H$_3$O$^+$ EtOH (excess) H$_2$SO$_4$, heat CI NH$_2$ Et$_3$N Br NaCN

          3. (24 points) Provide the major product(s) for each of the following reactions. If no reaction
occurs, indicate NR.
KMnO$_4$
H$_3$O$^+$, heat
SOCl$_2$
OH
CH$_2$Cl$_2$
H$_3$O$^+$
CEN
Heat
CI
CO$_2$H
4
1) CH$_3$CH$_2$MgBr
(2 eq.)
2) H$_3$O$^+$
1) LiAlH(O-t-bu)$_3$
2) H$_3$O$^+$
EtOH (excess)
H$_2$SO$_4$, heat
CI
NH$_2$
Et$_3$N
Br
NaCN

3. (24 points) Provide the major product(s) for each of the following reactions. If no reaction
occurs, indicate NR.
KMnO4
H3O^+, heat
SOCl2
OH
CH2Cl2
H3O^+
CEN
Heat
CI
CO2H
4
1) CH3CH2MgBr
(2 eq.)
2) H3O^+
1) LiAlH(O-t-bu)3
2) H3O^+
EtOH (excess)
H2SO4, heat
CI
NH2
Et3N
Br
NaCN

Added by Kelsey W.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Bridger Johnston

Step 1

KMnO4, HO, heat: This is a mild oxidation reaction. KMnO4 is a strong oxidizing agent that can convert alcohols to carbonyl compounds. In this case, the alcohol will be oxidized to an aldehyde or a ketone. The exact product will depend on the starting alcohol. Show more…

Show all steps

Thanks for your feedback!

Please help, studying for an exam tomorrow! 3.24 points: Provide the major product(s) for each of the following reactions. If no reaction occurs, indicate NR. 1. KMnO4, HO, heat 2. SOCI2, CHCl2, OH 3. HO*, NEOT, heat 4. 1CHCHMgBr 2eq., 2) HgO* 5. 1LiAIHO-t-bu)3, 2HO 6. EtOH (excess), HSO4, heat 7. COH, NH2, EtgN 8. e, Br, NaCN