(1) Use Fermat's Little Theorem and modular exponentiation to find \(51^{7310} \text{ mod } 101\) (note that 101 is a prime). (2) Using that 5 is a primitive root modulo 37, find \(log_5^{mod37}(11)\).
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In this case, p = 101 and a = 517310. Show more…
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