8 A tree BT is due north of an observer at P and due west of an observer at Q. The two observers are 50m apart and the bearing of Q from P is 36°. The angle of elevation of T from Q is 28°. a Show that BQ = 50sin 36°. b Hence find the height h of the tree, correct to the nearest metre. c Find the angle of elevation of T from P, correct to the nearest degree.
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We have a tree (T) and two observers (P and Q). The tree is due north of P and due west of Q. The distance between P and Q is 50m, and the bearing of Q from P is 36°. We need to find the distance BO (where O is the point directly below the tree T on the ground, Show more…
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