00:01
Hello students, in this question given as a resistance r2 is equal to 3 kω in the circuit and r3 is equal to 2 kω, r4 is equal to 1 kω and applied source voltage is equal to 12 v and the thermistor temperature which recorded from 60 degrees celsius to 130 degrees celsius.
00:36
Now we know that the formula voltage at the point b in the circuit is equal to the 12 r4 upon r2 plus r4.
00:52
So this will be equal to the 12 into r4 is equal to 1 kω is given upon r2, r2 is equal to 3 plus r1 is equal to 1 kω.
01:05
So this will be equal to the 3 volt and va point voltage at the point a is equal to the 12 r3 upon r3 plus thermistor resistance.
01:31
So this will be equal to the, now the voltage across the point ab.
01:39
So ab is equal to that will be va minus vb, this is equal to 12 and the value of r3 is 2 upon r3 is, we can write like this, r3 is 2 upon 2 plus r thermal.
02:10
So this will be equal to the 24 upon 2 plus r thermistor.
02:14
Now we can write here 24 upon 2 plus r thermistor minus 3, equation number 1.
02:30
Now we have written some values of thermistor resistance corresponding to the given temperature from 60 to 130 degrees celsius which is given in the question, in the table, the table of the question...