Mx25 6=1.6x 2.6×105 = 1.538×104 M 120=1.538×104 M Component...

Mx25 6=1.6x 2.6×105 = 1.538×104 M 120=1.538×104 M Component shown was machined from AISI 1040 Cold Rolled. D = 1.000 in., d = 0.625 in., Fillet between the major and minor diameter sections; r = 0.0625 in, at x = 4.75 in. from C. The length of AC is 71½ inches. 10 = 160 lbs If a load of P = (150 +YZ) lbs is applied at C, determine the factor of safety with respect to failure by yield in the fillet at B. Mmax = 7.8×105 N-mm

Transcript

00:01 Okay, for this particular problem, we want to determine the actual outer diameter of this pipe.

00:11 Okay? that is being subject to, it's subjected to the ten side force.

00:17 Right? so, so the diagram is not given, and just, i'm just, maybe my own, something like this.

00:28 So we have a tensile force of p equal to one point.

00:43 So fiber, we're given 1 ,500 kilo -newton, can just convert it to newton, same thing as 1 ,5 ,00 times 10, which is of the power of 3, newtine.

01:09 Okay, all right.

01:17 We are given that the thickness to 1 over 8, the outer diameter times the outer diameter.

01:35 All right the factor of safety helps you to yielding against yielding rather to 1 .8s here and the new stress is 290 mega pasta so let's just convert is to to pass our meeting per meter square so you have the same thing to give you to give you to give you two 290 times 10 ratio the power of 4 6 pascal or rating per meter square any one.

02:36 Those, all right.

02:39 So i've gotten this information.

02:41 We know that you can also just look for the area.

02:44 The area is equal to, you know, that is pi, these, the outer diameter, square, over four.

03:05 Minus the area for the inner diameter.

03:11 Okay? but we are given that the i, sorry, d -o minus d -i, yeah, the i is internal diameter, okay, d -o is the outer diameter, the inner diameter, all right? so we have been given already that this one is the same thing as a thickness.

03:50 It's also equal to the thickness t.

03:53 T is a thickness, okay? it will be 1 over 8...

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