Find the position vector R(t) given the velocity V(t) = (4t + 4) i + 8 sin(4t) j + 4t k and the initial position vector R(0) = -3i + 2j + 2k. R(t) =
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The velocity vector function is given as: V(t) = (t^4)i + (5sin(t))j + t^3k Now, we need to find the integral of each component: ∫(t^4)dt = (1/5)t^5 + C1 ∫(5sin(t))dt = -5cos(t) + C2 ∫(t^3)dt = (1/4)t^4 + C3 So, the position vector function is: F(t) = Show more…
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