00:01
Hi everyone in this question we have registers r1 r2 r3 r4 and r5 r1 is equal to om r2 is equal to 5 om r 3 is equal to 6 om r4 is equal 2 om and r5 equal to 7 o in party of the question we have to find out the equivalent resistance between the points a and b we take this equivalent resistance to equal to r equivalent if you observe this circuit, we'll find that this r2 and this r2 are in series r2 and r2, which are in series, we'll consider that their equivalent resistorsetances are equivalent 1.
00:53
Now, this r equivalent 1 and the resistor r3 are in parallel to each other.
01:06
We consider the equivalent here to be r equivalent to.
01:11
After this, r equivalent 2 and the resistance that is present here r1 are in c.
01:23
And now the equivalent ratio is considered as r equivalent 3.
01:29
R equivalent 3 and the resistor r4 are in parallel to each other.
01:42
Now the equivalent resistance is considered as r equivalent 4.
01:47
Then we'll have r equivalent 4, then r1 and r5 in series with each other.
01:53
Solving that, we'll get the equivalent resistance r equivalent.
01:56
For series and parallel connection, we know that the equivalent resistance for a series connection is equal to r1 plus r2 plus r3 and so on, where r1, r2, r3 are the different.
02:13
Distances also 1 divided by the equivalent resistance in a parallel connection is given by 1 divided by r 1 plus 1 divided by r 2 plus 1 divided by r 3 and so on so we will have r equivalent 1 is equal to r 2 plus r 2 which is equal to 5 plus 5 it is equal to then you have 1 divided by r equivalent 2 which is equal to 1 divided by r equivalent 1 plus 1 divided by r 3 this is equal to 1 divided by 10 plus 1 divided by 6 this is equal to 4 divided by 15 that means r equivalent 2 will be equal to 15 divided by 4 0 now we find out r equivalent 3 which will be equal to r equivalent to plus r 1 is equal to 15 divided by 4 plus equal to 20 % divided by 4 oom and now 1 divided by r equivalent 4 is equal to 1 divided by r equivalent 3 plus 1 divided by r 4 equal to 1 divided by 203 by 4 plus 1 divided by 2 this comes out as 31 divided by 46 so r equivalent 4 is equal to 46 divided by 31 home now we can find out the equivalent resistance of the circuit which is equal to r1 plus r equivalent 4 plus r5 let us put the values the equivalent resistance of the circuit will be equal to 2 om plus 46 divided by 31 om plus 7 .0.
04:33
This comes up to equal to 10 .5 om.
04:38
Therefore, the equivalent resistance between the points a and b is 10 .5 ome...